How can i have in results all the first results and all the second results regrouped?
0.3151
-0.3904
0.3412
-0.3416
0.3581
-0.2836

2 commentaires

KALYAN ACHARJYA
KALYAN ACHARJYA le 4 Fév 2019
How you got the results, share code?
I've solved...
I've a problem...
after this code, i obtain 14 2x2 matrix, how can i calculate the inverse of every matrix?
OA=1.42
AB=4.3
BO=3.33
OO=6
alfa=[19.7000, 10.2615, 0.8231, -8.6154, -18.0538, -27.4923, -36.9308, -46.3692, -55.8077, -65.2462, -74.6846, -84.1231, -93.5615, -103.0000];
beta= [37.3648, 40.5764, 43.6511, 46.4267, 48.7411, 50.4573, 51.4816, 51.7706, 51.3269, 50.1884, 48.4165, 46.0853, 43.2749, 40.0669];
gamma= [-68.0355, -66.333, -63.8261, -60.6513, -56.9882, -53.0279, -48.9467, -44.8871, -40.9515, -37.2048, -33.6824, -30.3996, -27.3598, -24.5623]
for i = 1:14
J = [AB*sind(beta(i)) BO*sind(gamma(i)); AB*cosd(beta(i)) BO*cosd(gamma(i))]
end

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 Réponse acceptée

Stephan
Stephan le 4 Fév 2019
Modifié(e) : Stephan le 4 Fév 2019

1 vote

Hi,
i assume you have the results in a form of:
res1 = [0.3151; -0.3904]
res2 = [0.3412; -0.3416]
res3 = [0.3581; -0.2836]
which looks like in your question:
res1 =
0.315100000000000
-0.390400000000000
res2 =
0.341200000000000
-0.341600000000000
res3 =
0.358100000000000
-0.283600000000000
Then you can do:
res = reshape([res1; res2; res3],2,[]);
group1 = res(1,:)'
group2 = res(2,:)'
which results in:
group1 =
0.315100000000000
0.341200000000000
0.358100000000000
group2 =
-0.390400000000000
-0.341600000000000
-0.283600000000000
Check the reshape function - it is very useful.
Best regards
Stephan

1 commentaire

No, unfortunately i've this;
0.2187
-0.3606
0.2738
-0.3349
0.3203
-0.3092
0.3581
-0.2836
they are not "named " (res1, res2)
How can i do to group together the first rows, and together the second rows?

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