Root finder matlab code is not displaying result

I wrote this code below. It works without errors. However I can't see the result.
It finds the nth root of w, starting from guess g.
w=9;
g=5;
n=2;
function result=findRoot(w,g,n)
if (abs(newGuess-g)<(g*0.0001))
result = newGuess;
disp(result);
else
newGuess = (g - g^n - w) / (n*g^(n-1));
result = findRoot(w, newGuess,n);
disp(result);
end
end
I appreciate any help. Thank you.

2 commentaires

One problem is that you are calling your function from within the function:
result = findRoot(w, newGuess,n);
This will lead to ‘infinite recursion’, and so no output.
Ceyda Elcin Kaya
Ceyda Elcin Kaya le 10 Fév 2019
Modifié(e) : Ceyda Elcin Kaya le 10 Fév 2019
Out of memory. The likely cause is an infinite recursion within the program.
yep the exact problem I'm facing with right now. I will try to find a solution.
edit: i made it i guess. only problem left is that now it displays infinetely
w=9;
g=5;
n=2;
findRoot(w,g,n);
function [result]=findRoot(w,g,n)
newGuess=0;
while(abs(newGuess-g)>g*0.0001)
newGuess = (g - g^n - w) / (n*g^(n-1));
%result = findRoot(w, newGuess,n);
disp(newGuess)
end
result = newGuess;
disp(newGuess);
end

Connectez-vous pour commenter.

Réponses (1)

Anand Shirke
Anand Shirke le 10 Fév 2019

0 votes

Maybe the problem is while declaring the function, I would suggest you to declare the function in this way
function [result]=findRoot(w,g,n)
..
.....
end
After saving the code, type in command window :
findRoot(9,5,2)

1 commentaire

I did what you say. Now I'm getting a new error.
Function with duplicate name "findRoot" cannot be defined.
But my function is defined.

Connectez-vous pour commenter.

Catégories

En savoir plus sur MATLAB dans Centre d'aide et File Exchange

Produits

Version

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by