plot integral equation coming from ode solver
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have an equation that comes from ode solver :
[t1 V1] = ode15s(dV1dt, t1, y1); plot(t1, V1 ,'-b','lineWidth',2)
then I do some basic addition or subtraction on it for eg :
Aout1=(V1-1); plot(t1,Aout1,'-b','lineWidth',2);
Now I wish to integrate the output : So I tried with
final = integral (Aout1, 0, 4.2)
But I get error :
Error using integral (line 82) First input argument must be a function handle.
I tried other things as well; but I don't achieve what I wish. Although 'cumsum' works well on it just like that.
0 commentaires
Réponse acceptée
Star Strider
le 15 Fév 2019
8 commentaires
Amirah Algethami
le 20 Août 2023
thanks @Torsten this extract with defining dV2/dt = V1-1 , I thought ode15 will be integrated it without using integral function? please clarify it for me.
Thanks
Torsten
le 20 Août 2023
Modifié(e) : Torsten
le 20 Août 2023
If you call ode15s with the additional ODE dV2/dt = V1(t)-1, V2(tspan(1)) = 0, ode15s will return
V2(i) = integral_{t=tspan(1)}^{t=tspan(i)} (V1(t)-1) dt (1 <= i <= end)
in the solution column for V2 in Y. The call somehow looks like
[T,Y] = ode15s(dVdt,tspan,[V1,0])
If you have further questions, please include executable code and mark the line where you have difficulties.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Numerical Integration and Differentiation dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!