Matrix multiplication and addition
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
suppose i have two matrices:
a= [1 0 0 2 0 6
1 0 0 2 0 7
1 0 0 2 0 8
1 0 0 2 0 9
1 0 0 2 0 10]
b= [ 1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5 6 7 8 9
6 7 8 9 10
7 8 9 10 11
8 9 10 11 12]
i need to consider only 6th coloumn in my 'a' matrix i.e only [6;7;8;9;10]. size of 'a' matrix will be 5x1 now. And from 'b' matrix only 1st fours rows need to be considered. New size of 'b' matrix will be 4x5. Then, the following operation needs to be done between new 'a' and new 'b' matrix:
r= 6x1+7x2+8x3+9x4+10x5
s=6x2+7x3+8x4+9x5+10x6
t=6x3+7x4+8x5+9x6+10x7
u=6x4+7x5+8x6+9x7+10x8
sum=r+s+t+u
How should the matlab code be written for the above operation?
0 commentaires
Réponses (2)
Kevin Phung
le 19 Fév 2019
m1 = a(:,6);
m2 = b(1:4,:)';
prod = m1.*m2;
part_sums = sum(prod);
r = part_sums(1);
s = part_sums(2);
t = part_sums(3);
u = part_sums(4);
total_sum = r + s + t + u;
% or you can just do sum(sum(prod)) and skip the r s t u
0 commentaires
Star Strider
le 19 Fév 2019
If I understand correctly what you want to do, this works:
Result = sum(b(1:4,:) * a(:,6));
producing:
Result =
760
0 commentaires
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!