How can i loop a matrix without knowing is size?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Joana Santos
le 1 Mar 2019
Modifié(e) : Joana Santos
le 1 Mar 2019
Hello!
So, i'm trying to make a loop where i have a matrix to go through and save their elements in a vector. Just note that i don't know the size of the matrix. So how can i do it?
Thanks!
2 commentaires
Réponse acceptée
Bob Thompson
le 1 Mar 2019
So, you have two matrices, one outside the loop, and one inside? Which one are you not sure about the size of?
If it is the outside loop you can set the loop bounds to be dependent on the size of the matrix.
for i = 1:size(mat,1) % (mat,1) for rows, (mat,2) for columns and so on
6 commentaires
Bob Thompson
le 1 Mar 2019
It's your indexing for v. Your i loop only goes from 1:2, so indexing v with (i) will just give you v(1) or v(2). You need to change this to be a combination of i and j.
v((i-1)*size(mat,2)+j) = mat(i,j);
Also, you need to change your dimension your specifying for the innner loop. When you call size() the first input is the matrix, and the second input is the dimension. 1 is rows, 2 is columns, 3 is sheets, etc.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!