Convert Time (string) to Time (numeric)

Right now I have a vector string which is a 130611 x 1 string.

This string contains values such as:

The first row is 0 hrs 5 mins 0 secs, second row is 0 hrs 5 mins 0 secs, third row is 0 hrs 13 mins 0 secs etc.

I would like to return the same sized vector but telling me only minutes?

For instance "01:10:00" would return 70.

Answer 1

[Star Strider]

You can use the datetime data type (with a few alterations, since duration for some reason does not accept datetime objects as arguments, or at least does not when I try it):

dtv = datevec(datetime({'00:05:00';'01:10:00';'23:59:59'},'InputFormat','HH:mm:ss'));
da = duration(dtv(:,4:end));
mins = minutes(da)

producing:

da = 
   00:05:00
   01:10:00
   23:59:59

mins =
            5
           70
         1440

I posted ‘da’ to demonstrate the conversion. It is not necessary to return it specifically.

The duration data does not ‘wrap’ unless you also supply the year-month-day values, so as long as your data are all in the same 24-hour day, they will be accurate.