Plot best fit line in log-space & get slope

I am trying to determine the slope of the best-fit line in log space, and plot the best-fit line as a visual check. It needs to be a line, not a curve (I understand that the misfits could be very large in logspace). Below is an example with xy data and polyfit attempts (and plot included). Thanks for any help
x = [7.94, 16.23, 32.92, 66.8, 135.52, 274.93, 557.78, 1131.59, 2295.72, 4657.46];
y = [134000, 102000, 31000, 11000, 2600, 990, 40, 10.41, 3.48, 1.037];
scatter(x,y, 'DisplayName', 'MyData')
set(gca,'xscale','log')
set(gca,'yscale','log')
hold on
grid on
box on
axis equal
p = polyfit(log10(x), log10(y), 1);
z = polyval(p, log10(x));
loglog(x, log10(z), 'DisplayName', 'Try1');
loglog(x, z, 'DisplayName', 'Try2');
z2 = polyval(p, x);
loglog(x, z2, 'DisplayName', 'Try3');
loglog(x, log10(z2), 'DisplayName', 'Try4');
legend
Capture.JPG

 Réponse acceptée

Star Strider
Star Strider le 27 Juil 2019
You are regressing ‘log10(x)’ against ‘log10(y)’ so you need to give the appropriate information to both polyfit and polyval:
Bp = polyfit(log10(x), log10(y), 1);
Yp = polyval(Bp,log10(x));
figure
plot(log10(x), log10(y), 'pg')
hold on
plot(log10(x), Yp, '-r')
hold off
grid
producing this plot:
The slope is -2.0182.

4 commentaires

newbie9
newbie9 le 3 Août 2019
the fit needs to be a straight line in logspace, not linspace
O.K., try this:
x = [7.94, 16.23, 32.92, 66.8, 135.52, 274.93, 557.78, 1131.59, 2295.72, 4657.46];
y = [134000, 102000, 31000, 11000, 2600, 990, 40, 10.41, 3.48, 1.037];
Bp = polyfit(log10(x), log10(y), 1);
Yp = polyval(Bp,log10(x));
figure
loglog(x, y, 'pg')
hold on
loglog(x, 10.^Yp, '-r')
hold off
grid
expstr = @(x) [x(:).*10.^ceil(-log10(abs(x(:)))) floor(log10(abs(x(:))))]; % Mantissa & Exponent
Bp2 = expstr(10^Bp(2));
eqn = sprintf('y = %.2f\\times10^{%d}\\cdotx^{%.2f}',Bp2(1), Bp2(2), Bp(1));
legend('Data', eqn)
Same essential code & plot, different axes scales:
Plot best fit line in log-space & get slope - 2019 08 03.png
Experiment to get it to look the way you want.
newbie9
newbie9 le 3 Août 2019
thanks, that's what I have below
Star Strider
Star Strider le 3 Août 2019
As always, my pleasure.
I was working on it as you were posting.

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Plus de réponses (1)

newbie9
newbie9 le 3 Août 2019
Star Strider basically gave the correct answer, so I have accepted; but I wanted to show the fit in log-log space, so here's my version of code, considering Star Strider's answer, in case it is useful to anyone else:
x = [7.94, 16.23, 32.92, 66.8, 135.52, 274.93, 557.78, 1131.59, 2295.72, 4657.46];
y = [134000, 102000, 31000, 11000, 2600, 990, 40, 10.41, 3.48, 1.037];
scatter(x,y, 'DisplayName', 'MyData')
set(gca,'xscale','log')
set(gca,'yscale','log')
hold on
grid on
box on
axis equal
%
Bp = polyfit(log10(x), log10(y), 1);
Yp = polyval(Bp, log10(x));
Yp2 = 10.^(Yp);
%
plot(x, Yp2, '-r', 'DisplayName', 'Fit');
text(1.1, 10, strcat('Slope in Log-Log Space =', num2str(Bp(1))), 'Interpreter', 'none');
legend
Which yields this plot:
untitled.jpg

1 commentaire

Angie Brulc
Angie Brulc le 7 Mar 2022
Hello,
I'm a random student working on processing data for a lab and just wanted to let you know this was incredibly helpful to me. Thank you!

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