I have a 1*1 cell in which its content is ineger. I need to convert the content to integer (no cell anymore just like a number itself)
how can I do that?
I tied cell2mat but did not work. It is like this now:
kar =
1×1 cell array
{[3]}

3 commentaires

Adam Danz
Adam Danz le 16 Août 2019
Modifié(e) : Adam Danz le 16 Août 2019
"I tried cell2mat but it did not work"
What does that mean? Did you get an error? If so, what was the full error message? If your example accurately describes your data, it should work.
kar = {[3]};
cell2mat(kar)
% ans =
% 3
madhan ravi
madhan ravi le 16 Août 2019
whos kar % Paste the results from command window here
Adam Danz
Adam Danz le 16 Août 2019
Modifié(e) : Adam Danz le 16 Août 2019
While you're at it, let us know what this returns or if it returns an error, too.
class(kar{:})
size(kar{:})

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Réponses (1)

Star Strider
Star Strider le 16 Août 2019

2 votes

If ‘kar’ is initially:
kar = {{[3]}};
try this:
n = cell2mat(kar{:})
producing:
n =
3

2 commentaires

Zeynab Mousavikhamene
Zeynab Mousavikhamene le 16 Août 2019
I get this error:
>> cell2mat(kar{:})
Brace indexing is not supported for variables of this type.
Error in cell2mat (line 36)
if isnumeric(c{1}) || ischar(c{1}) || islogical(c{1}) || isstruct(c{1})
Zeynab Mousavikhamene
Zeynab Mousavikhamene le 16 Août 2019
Initially kar is :
kar =
1×1 cell array
{[3]}

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