# Saving Data In A For Loop Into An Array

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Hans123 on 20 Aug 2019
Commented: Star Strider on 13 Sep 2019
This seems like a basic question, but I can't seem to figure it out.
I have data for multiple spirals and I want all the x,y and z co-ordinates for each spiral in seperate arrays. I cannot preallocate because I am not aware of the size before running the code.
Would really appreciate any help on how to save my co-ordinates for each spiral in seperate arrays. The code is pasted below
clc; clear; close all
spirals = (1:10:61);
dy = max(spirals);
indent = linspace(-255+dy, 255-dy,4);
num = 1:1:7;
cla
hold on
layerheight = [1 2 4 5];
for columns=1:4
for rows = 1:length(spirals)
center = -250 + (spirals(rows))*num(rows);
gap=layerheight(columns);
d=layerheight(columns);
r = spirals(rows);
z=(linspace(0,d,10000));
t=(40*pi/gap)*z;
x=round(r*cos(t)+center);
y=round(r*sin(t)+ indent(columns));
plot3(x,y,z,'o','MarkerSize',2)
% for counter = 1:length(z)
% rowdata(counter) = [x(rows) y(rows) z(counter)]; %this is how I thought of saving the data, but it doesn't work
% end
end
end
hold off
xlim([-255 255])
ylim([-255 255])
zlim([0 5])
grid on
ylabel('\it Increasing Layer Height \leftarrow')

Star Strider on 20 Aug 2019
The easiest way would probably be to save them all in separate cell arrays, here ‘xc’, ‘yc’, and ‘zc’:
for columns=1:4
for rows = 1:length(spirals)
center = -250 + (spirals(rows))*num(rows);
gap=layerheight(columns);
d=layerheight(columns);
r = spirals(rows);
z=(linspace(0,d,10000));
t=(40*pi/gap)*z;
x=round(r*cos(t)+center);
y=round(r*sin(t)+ indent(columns));
plot3(x,y,z,'o','MarkerSize',2)
% for counter = 1:length(z)
% rowdata(counter) = [x(rows) y(rows) z(counter)]; %this is how I thought of saving the data, but it doesn't work
% end
xc{rows,columns} = x;
yc{rows,columns} = y;
zc{rows,columns} = z;
end
end
Experiment to get the result you want.

Star Strider on 20 Aug 2019
I cannot find any reference to a ‘writefile’ function. The writecell function was introduced in R2019a.
I am not certain how you want to write them. Note that each cell array has 28 elements, each of which is a (1x10000) vector.
Each circle would be described as a (3x10000) matrix. It might be easiest to save each circle ‘X’, ‘Y’, and ‘Z’ vector to a separate sheet of a spreadsheet file (such as Excel), although saving them as their transposes (so a (10000x3) matrix for each) would likely be easier. That will significantly reduce any problems you may have in importing them again. Use the xlswrite function for that. This could easily be programmed in a loop, using the sprintf function to create the matrices for each circle, and the command strings for xlswrite.
Hans123 on 13 Sep 2019
StarStrider! My apologies for getting back to you this late. I figure out the answer and I forgot that I reached out for you for help!
Again I am really sorry.
Thanks for your help, I always appreciate it!
Star Strider on 13 Sep 2019
No worries!
As always, my pleasure!