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why im not able plot graph in 1 sec window of 16 sample

Asked by germanbrain common on 25 Aug 2019 at 8:54
Latest activity Commented on by Image Analyst
on 27 Aug 2019 at 11:28
clc;clear all; close all;
A=1;
x=0:0.1:1;
sample=16;
y=A*sin((2*pi./sample)*x)
figure
plot(x,y)
untitled.jpg

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In one sec window i have to plot sine wave with 16 points.
dpb
on 25 Aug 2019 at 14:47
x=linspace(0,1,16);
y=A*sin(2*pi*x);
plot(x,y)

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1 Answer

Answer by Image Analyst
on 25 Aug 2019 at 16:19
 Accepted Answer

You didn't have anough points to see the sine wave so all you see is a traingle wave. Increase the number of points and use linspace():
numPoints = 50; % Whatever
Amplitude = 1;
t = linspace(0, 1, numPoints);
period = 0.4; % Seconds -- whatever you want;
y = Amplitude * sin((2*pi./period) * t)
plot(t, y, 'bo-', 'LineWidth', 2, 'MarkerSize', 9)
grid on;
xlabel('Time', 'FontSize', 13);
ylabel('Y', 'FontSize', 13);
title('Sine Wave', 'FontSize', 13);
0000 Screenshot.png

  3 Comments

thank you, but one question i am having here here my input signal is 1 sec or 1hz fre and what about sampling frequnecy here??
Fs is how much?
PS: I need one full cycle in 1 second,in your plot i can se 2.5 cycle.
Change the period value, and see the results.
fs (omega) is (2*pi/period). For a 1 second, 1Hz chunk of signal, you'll have one wave of the sine wave. You can pick whatever sampling rate you want. Of course the higher it is, the more accurately you'll draw the signal.

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