Write a script that given a vector, called A, of n numbers, outputs the index of the first number divisible by 3. Sample Output: Given A = [5, 4, 6, 7, 3] divisible by 3 is:3

The index first number divisible by 3 is: 3

but I do not know how to get the position from the vector.

Answer 1

[KALYAN ACHARJYA]

A = [5, 4, 6, 7, 3];
idx=find(mod(A,3)==0); % Gives the index number / Position
disp(A(idx)); % Gives the those idx number in A

[Shuoze Xu]

The first number can be divided by 3 is 6,

6 is the third number in this vector, so the position of first number is 3.

i want to know how to get ouput of position is 3 in this question

[KALYAN ACHARJYA]

In A there are two numbers, which are divisible by 3, numbers are 6 (position 3) and 3 (position 5)

A = [5, 4, 6, 7, 3];
idx=find(mod(A,3)==0)   % This line gives the index position

Result:

idx =
     3     5

If you are interested to know the those index position number, use

disp(A(idx));