MATLAB Answers

luca
0

Remove NaN inside a loop cycle

Asked by luca
on 16 Sep 2019
Latest activity Answered by Star Strider
on 16 Sep 2019
Given the following code
V = [ 19 15 11 2 16 3 1 18 14 3 18 19 1 13 16 14 19 15 4 14 3 1 2 16 4 3 1 19 3 20 4 13 1 15 2 18 4 1 19 17 3 1 13 3 4 17 18 19 14 ;
19 16 11 2 16 15 1 18 14 3 18 19 14 2 16 14 19 15 4 14 3 11 2 16 4 3 1 19 3 20 4 13 1 4 2 18 4 1 19 17 3 19 13 3 4 17 18 19 14 ];
A= [0 15 11 2 4 0 3 1 13;
14 0 16 0 0 0 0 0 0;
0 0 0 0 8 0 0 0 0;
0 0 18 0 0 0 0 0 0;
0 0 19 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0];
%V = [V(1,:), NaN(1, mod(-size(V,2), 10))];
for i= 1:size(V,1)
VVV = [V(i,:), NaN(1, mod(-size(V,2), 10))];
%assert(mod(numel(V), 10) == 0, 'V length is not a multiple of 10');
V10 = reshape(VVV, 10, []); %rearrange V in batches of 10
[~, where] = ismember(V10, A); %find location of elements in A
[~, col] = ind2sub(size(A), where); %convert location into column index
[~, order] = sort(col, 1); %and sort by column order
X (i,:) = reshape(V10(order + (0:size(order, 1):numel(order)-1)), 1, []); %and rearrange columns of V10 according to that order
B(i,:) = X(~isnan(X(i,:)))';
end
I'm generating a matrix X where inside are contained some NaN. How can I remove the NaN inside the rows?
the code
B(i,:) = X(~isnan(X(i,:)))';
does not work!
The number of NaN is the same in each rows, so we don't need to use cells
May someone help me?

  0 Comments

Sign in to comment.

Products


Release

R2019b

1 Answer

Answer by Star Strider
on 16 Sep 2019
 Accepted Answer

Try this:
B(i,:) = X(i,~isnan(X(i,:)));

  0 Comments

Sign in to comment.