How can I Write a code that will allow a vector of positive integers in x, as a user input, to evaluate the equation listed below.For odd numbers we will use the following equation
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x= input('\nPlease input a 5 values in vector notation:');
i = 1;
for i = 1:5
if rem(i,2) ==1; i = 2.*(i.^2) + 8*i - 3;
if rem(i,2)==0;
i = 2.*(i.^2) - 8*i + 3;
end
end
i=i+1
end
disp(i)
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dpb
le 18 Sep 2019
x= input('\nPlease input a 5 values in vector notation:');
b=nan(size(x)); % initialize to something
isodd=mod(x,2)==1;
y(isodd) =polyval([2 8 -3],x(isodd); % evaluate 2x.^2 + 8x - 3 for odd x
y(~isodd)=polyval([2 -8 3],x(~isodd); % evaluate 2x.^2 - 8x + 3 for even x
disp(y)
3 commentaires
dpb
le 18 Sep 2019
Sure... :)
Just carry on as you began with rough93 pattern incorporating my comments...since it is homework, let's see your continuing work towards a solution rather than just "giving away the store"....will continue to provide hints or answer specific questions other than "just do it"... :)
Plus de réponses (1)
rough93
le 18 Sep 2019
It looks like you're using i within your calculations when you should be using x. Assuming your vecor input is [1 2 3 4 5]:
i = 1;
for i = 1:5
if rem(x(1),2) ==1; x = 2.*(x.^2) + 8*x - 3;
if rem(x,2)==0;
x = 2.*(x.^2) - 8*x + 3;
end
end
i=i+1
end
You may also want to make your second if an ifelse and add an else condition to clean up the code and prevent errors.
1 commentaire
dpb
le 18 Sep 2019
Modifié(e) : dpb
le 18 Sep 2019
The if above for rem(x,2)==0 won't work as it returns a logical vector which will be true only if all elements are true. Need to test x(i) in the loop.
The assignment is also global and overwrites the input x vector in the calculations.
Also incrementing i is automagic in the loop for expression and neither the initialization before the loop nor the incrementing statement are of any use and should be eliminated entirely.
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