how three vectors store in 3d array of zeros of same size with each vector's size

v1=[1 2];

>> v2=[1 2 3];

>> v3=[1 2 3 4];

>> m=zeros(2,3,4);

how v1,v2 and v3 are stored in 'm' array.

thanks in advance for help

[ME]

Could you possibly give your desired result? That would help in understanding your question.

Answer 1

[KALYAN ACHARJYA]

One way:

data=zeros(4,1,3);
v1=[1 2];
v2=[1 2 3];
v3=[1 2 3 4];
v1(length(v3))=0; % Because v3 having maximum length
v2(length(v3))=0;
data(:,:,1)=v1;
data(:,:,2)=v2;
data(:,:,3)=v3;

There may be more efficient way to do this

Result:

data(:,:,1) =
     1
     2
     0
     0
data(:,:,2) =
     1
     2
     3
     0
data(:,:,3) =
     1
     2
     3
     4

[Olawale Akinwale]

My approach would be

m = zeros(3,max([length(v1),length(v2),length(v3)]));
m(1,1:length(v1)) = v1;
m(2,1:length(v2)) = v2;
m(3,1:length(v3)) = v3;