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Functions Matlab, how to modify?

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Jenny Andersen
Jenny Andersen le 24 Nov 2019
Commenté : Jenny Andersen le 25 Nov 2019
Hi,
so I have two vectors, Q = (a,l,m) and Z = (d,b,c). I have created a function to calculate Z, but the problem is that I don't want the answear to be d= something1, b=something2 and c= something3. I want it to be Z = =[something1, something2, something3] when I call the function.
function [a,l,m]=test1(d,b,c)
a=0;
l=b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
a=a*1;
a=a*-1;
l=l*1;
l=l*-1;
m=m*1;
m=m*-1;
Is it possbible to modify the function in some way to achive this?
  2 commentaires
Turlough Hughes
Turlough Hughes le 24 Nov 2019
You would write
function Z = test1(d,b,c)
% operations to get a,l,m.
Z=[a l m];
end
KALYAN ACHARJYA
KALYAN ACHARJYA le 25 Nov 2019
Modifié(e) : KALYAN ACHARJYA le 25 Nov 2019
function Z = test1(d,b,c)
a=0;
l=b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
a=a*1;
a=a*-1;
l=l*1;
l=l*-1;
m=m*1;
m=m*-1;
Z=[a l m];
fprintf('Z=[%i %i %i]\n',Z);
end

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Réponse acceptée

Turlough Hughes
Turlough Hughes le 25 Nov 2019
Modifié(e) : Turlough Hughes le 25 Nov 2019
Hi Jenny,
You could write your function to have two outputs as follows:
function [Z1,Z2] = test1(d,b,c)
% code to determine a,l,m
Z1=[a,l,m];
Z2=[a,-l,-m];
end
When calling the function you have to specify two outputs if you want them otherwise matlab does not know what to assign the second output to. Basically:
[Z1,Z2]=test1(d,b,c)
Another thing you could do would be to write a single output where you have 6 elements in a single output variable. That would go something like this:
function Z = test1(d,b,c)
% code to get a,l,m
Z=[a,l,m;a,-l,-m];
end
When you call the function now you get a single output with six elements that you are looking for.
I recommend looking at onramp tutorials. Especially part 7 on calling functions as well as vectors and matrices, part 3. Though, if you intend to use matlab much you are as well to go through all of the sections.
  1 commentaire
Jenny Andersen
Jenny Andersen le 25 Nov 2019
Thank you alot! It seems to be working very well now. One thing that came to mind is that the value differs a bit from be previous expressions, but I gess that is the way functions work.
I will continue with the Onramp course.

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Plus de réponses (1)

Jenny Andersen
Jenny Andersen le 25 Nov 2019
Modifié(e) : Jenny Andersen le 25 Nov 2019
So I tried Turlough's suggestion again and it seems to be working fine now. But since two vectors will be generated (-d,b,c) and (d,b,-c) I would like to add this information to my code in some way. I have come up with the following, but still I only get one vector.
function [Z] = test1(d,b,c)
a1=0;
l1=b/sqrt(b^2 + c^2);
m1=-c/sqrt(d^2 + c^2);
a=0;
l=-b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
Z=[a1 l1 m1];
Z=[a l m];
end
  1 commentaire
KALYAN ACHARJYA
KALYAN ACHARJYA le 25 Nov 2019
Modifié(e) : KALYAN ACHARJYA le 25 Nov 2019
Why you have deleted your previous comments, its may confuse to the answer providers? This is answer section, please post your comment in comment section only.

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