Passing parameters in boundary value problem using BVP4C

51 vues (au cours des 30 derniers jours)
Saeid
Saeid le 1 Déc 2019
For a system of boundary value problems I need to pass a parameter as a coefficient. Let's assume that I have defined the problem as:
solinit = bvpinit(linspace(0,10,50),[0 10]);
sol = bvp4c(@twoode,@twobc,solinit,a);
x = linspace(0,4);
y = deval(sol,x);
function dydx = twoode(x,y,a)
dydx = [ y(2); -a*exp(-x)+x*exp(-x)];
end
function res = twobc(ya,yb,a)
res = [ya(1); yb(1)-10*exp(-10)];
end
Where a is the parameter, and my first try was to add a to all the functions involved, but I receive the "Not enough input arguments" error. Is there a way to include the parameter a in the problem?

Réponse acceptée

Star Strider
Star Strider le 1 Déc 2019
Define ‘a’ in your workspace, then use this bvp4c call:
sol = bvp4c(@(x,y)twoode(x,y,a),@(ya,yb)twobc(ya,yb,a),solinit);
You are passing the extra parameter correctly, however bvp4c does not need to know about it, so only show bvp4c the arguments it wants, thus:
@(x,y)twoode(x,y,a)
and:
@(ya,yb)twobc(ya,yb,a)
The anonymous function construction (that you wrote correctly) will pick up ‘a’ from your workspace and pass it to your functions.
With this change (and specifying ‘a’), your code ran without error with this bvp4c call when I tested it.
  3 commentaires
Star Strider
Star Strider le 2 Déc 2019
As always, my pleasure!
I very much appreciate your compliment!
Christian Chamberlayne
Christian Chamberlayne le 20 Mar 2020
This is super helpful. I simularly was stuck with the same issue. Thank you!

Connectez-vous pour commenter.

Plus de réponses (1)

Stephan
Stephan le 1 Déc 2019
See here: passing extra parameters. I suggest to either use the anonymous functions or the nested functions approach. Both is easy to apply.
  1 commentaire
Saeid
Saeid le 2 Déc 2019
Thanks Stephan! I just did and it worked!

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by