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bar figure with stacked

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Brave A
Brave A on 3 Dec 2019
Commented: Adam Danz on 4 Dec 2019
y = [11 4 3;8 7 2;11 2 3;7 4 5; 12 2 2;10 3 3; 10 3 1; 7 5 2;11 1 1;4 5 3;7 3 1];
x = categorical({'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','i','o'});
x = reordercats(x,{'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','p','l'});
bar(x,y,'stacked');
Hi I would like to have stacked for y and x also.
Would you help me in that because it gave error.
Thanks in advance

  2 Comments

Star Strider
Star Strider on 3 Dec 2019
The error is:
Error using categorical/reordercats (line 38)
NEWORDER must be a permutation of the existing categories.
The obvious solution is not to introduce new categories.
Brave A
Brave A on 3 Dec 2019
Could explain more?

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Accepted Answer

Adam Danz
Adam Danz on 4 Dec 2019
Edited: Adam Danz on 4 Dec 2019
You've got an error/typo in reordercats().
x = categorical({'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','i','o'});
x = reordercats(x,{'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','p','l'});
% HERE----------------------------------------------------------------------------------------^---^
You can't rename the categories. You can only specify their order.
This works, below.
y = [11 4 3;8 7 2;11 2 3;7 4 5; 12 2 2;10 3 3; 10 3 1; 7 5 2;11 1 1;4 5 3;7 3 1];
x = categorical({'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','i','o'});
x = reordercats(x,{'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','i','o'});
% ------------------------------------------------------------------------or maybe you want 'o','i'}); ??
bar(x,y,'stacked');

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Brave A
Brave A on 4 Dec 2019
Based on numbers as decen order.
Brave A
Brave A on 4 Dec 2019
y = [ 11 4 3;11 2 3 ; 11 1 1; 10 3 1;7 3 1;7 5 2; 12 2 2;10 3 3; 4 5 3 ;8 7 2 ;7 4 5];
% [ ]
[sd,r]=sort(y,'descend')
x = categorical({'Pointers','Basic function calling/program flow','Variable/function declarations','Operators and precedence','Conditional operations','Looping operations ','Scope of variables','Input/and file handling','Arrays','Recursion','String handling'})
bar(x,[sd,r],'stacked'
I tried thid but it's repeat the values and not sorting them.
Adam Danz
Adam Danz on 4 Dec 2019
y is a matrix with 3 columns. What are you sorting? If you're sorting by stacked bar height, you need to sum the rows of y and this will result in the same order as what you've got already.
y = [11 4 3;8 7 2;11 2 3;7 4 5; 12 2 2;10 3 3; 10 3 1; 7 5 2;11 1 1;4 5 3;7 3 1];
x = categorical({'Python','Java',' C++','Matlab', 'C','C#','Visual Basic','Processing','R','i','o'});
[~,r]=sort(sum(y,2),'descend'); % Sum rows of y
x = reordercats(x,cellstr(x(r))); % use reordercats()
bar(x,y(r,:),'stacked');

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