Matrix dimension must agree

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Saskia Nur Santika
Saskia Nur Santika le 9 Jan 2020
Ihave a code
xd=-(sqrt(R²-ho²)):0.5:x3;
xd1=x3;
yd1=y3;
xd2=-(sqrt(R²-ho²));
yd2=ho;
yd=(((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
plot(xd,yd,'k')
The result is:
Eror using .* Matrix dimensions must agree.
Please help mee ?
*code formatted by Adam Danz; the squared superscripts are ambiguous (^2 or .^2) so I left them as-is - AD
  3 commentaires
David Hill
David Hill le 9 Jan 2020
You need to provide more information. Look at the size of each of your matrixes. If you want help you will need to provide examples of your variables.
Saskia Nur Santika
Saskia Nur Santika le 9 Jan 2020
f=15; R=2*f; ho=12; so=10; sia=-((f*so)/(f+so)) x3=-r-sia

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Réponse acceptée

Adam Danz
Adam Danz le 9 Jan 2020
In this line
yd = (((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
% ^^
The terms to the left and right of .* are not the same size. The dot-asterisk notation specifies element-wise multiplication where x .* y is interpretted as x(i) * y(i). That requires that x and y are the same size.
The two lines below must produce the same output.
size(((xd-xd1)./(xd2-xd1)))
size((yd2-yd1))
  2 commentaires
Saskia Nur Santika
Saskia Nur Santika le 9 Jan 2020
Thankyouu
KALYAN ACHARJYA
KALYAN ACHARJYA le 9 Jan 2020
If your question is answered, you can accept the answer.

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Plus de réponses (1)

Mateus Banroc
Mateus Banroc le 9 Jan 2020
Hi Saskia,
In your code, I guess that only xd and yd are vectors, right? So x3, y3, R and ho should be scalars.
I don't know what are the values of these scalars but I tried this and it worked.
R=10; ho=2;
x3=10;
y3=10;
xd=-(sqrt(R^2-ho^2)):0.5:x3;
xd1=x3;
yd1=y3;
xd2=-(sqrt(R^2-ho^2));
yd2=ho;
yd=(((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
plot(xd,yd,'k')
You must check if R, ho, x3, y3 are scalars.
  1 commentaire
Saskia Nur Santika
Saskia Nur Santika le 9 Jan 2020
Yeah, thankyou so much.

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