Seperate rows in matrix based on values of the elements.

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Mike Mierlo van
Mike Mierlo van le 2 Mar 2020
Hi,
I have simplified my 'multiple radar' problem into this: Lets say I have matrix A, consisting of columns 1 (timestamp) and 2 (value). I want obtain matrices that have ascending timestamps and the difference between the values in column 2 of the new vectors must not be greater than 5.
%Input matrix [timestamp values]
A= [0 100;
0 400;
0 500;
1 103;
1 397;
1 502;
2 506;
2 104;
2 399];
%Now magic happens
%Output matrices per radar [timestamp values]
OUT1= [0 100;
1 103;
2 104];
OUT2= [0 400;
1 397;
2 399];
OUT3= [0 500;
1 502;
2 506];
Hopefully somebody can help me out of this misery

Réponse acceptée

KALYAN ACHARJYA
KALYAN ACHARJYA le 2 Mar 2020
Modifié(e) : KALYAN ACHARJYA le 2 Mar 2020
for i=1:length(unique(A(:,1)))
mat{i}=A(A(:,1)==i-1,:);
end
result=cell2mat(mat)
out1=reshape(result(1,:),[2,3])' % Use loop for 3 statements
out2=reshape(result(2,:),[2,3])'
out3=reshape(result(3,:),[2,3])'
# This may be possible without loop also, recomended
  6 commentaires
Mike Mierlo van
Mike Mierlo van le 2 Mar 2020
Thank you! Now I get the same output. But the output matrices do still not meet the requirement:
  • the difference in advancing indexes of column 2 must not be greater than 5.
Any solution for this part?
Mike Mierlo van
Mike Mierlo van le 2 Mar 2020
Found it myself. result=sort(result) will do the job.
Thanks for the help!!!

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