i want to generate a sequence of n numbers

453 vues (au cours des 30 derniers jours)
Matte Rennerts
Matte Rennerts le 9 Mar 2020
Réponse apportée : Voss le 19 Oct 2023
How would i generate a secuence of N amount of numbers starting at -4 and going up in steps of 2?
Cheers
  3 commentaires
Matte Rennerts
Matte Rennerts le 9 Mar 2020
Those sequence codes work if i have an end value of the secuence but i need the sequence to contain n amount of elements regardless of the last value
Robert U
Robert U le 9 Mar 2020
Those sequences work with variables as end values as demonstrated in the answer by Benni.

Connectez-vous pour commenter.

Réponse acceptée

Benjamin Großmann
Benjamin Großmann le 9 Mar 2020
Modifié(e) : Benjamin Großmann le 9 Mar 2020
You can create sequences with the colon operator (:), for exapmle
v = [4:2:100];
creates v = [4, 6, 8, ... , 100] with values starting at 4, an increment of 2 and stop value 100.
For N numbers starting at -4 and an increment of 2, you have to calculate the stop value:
N = 10;
start_val = -4;
inc = 2;
stop_val = (N-1)*inc + start_val;
v = [start_val:inc:stop_val];

Plus de réponses (1)

Voss
Voss le 19 Oct 2023
start = -4;
increment = 2;
N = 8;
sequence = start + (0:N-1)*increment;

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by