Finding decimal values without mod

Is it possible or is there any way to find a value in an array that is a decimal without using mod(or any other function)?

[Ameer Hamza]

By decimal value, do you mean a fractional number. Do you want to seperate fractional numbers from integers?

[James Tursa]

Please provide a small example of input and desired output.

[Jose Grimaldo]

For example, i want to separate the odd and even integers. I know there is easier ways,but i cant use functions only loops. (its a hw problem)

A=[1; 2; 3; 4; 5; 6; 7; 8]

[r,c]=size(A)

for i=1:r

if (i/2) = % Need help in the if condition

EvenV=i % I want to store the Even integers

elseif (i/2) ~= % Need help in the if condition

OddV=i % i want to store the odd integers

end

[KALYAN ACHARJYA]

"For example, i want to separate the odd and even integers. I know there is easier ways,but i cant use functions only loops. (its a hw problem)"

You asked for with loop and without mod function, you can do multiple ways-

A=[1; 2; 3; 4; 5; 6; 7; 8]
m=1;n=1;
for i=1:length(A)
    if rem(A(i),2)==0
    EvenV(m)=A(i); % I want to store the Even integers
    m=m+1;
    else 
    OddV(n)=A(i); % i want to store the odd integers
    n=n+1;
    end 
end
    EvenV
    OddV

[James Tursa]

You are going to have to use some functions for this. Even the / you are currently using is a function. Which functions are explicitly forbidden?

Answer 1

[Ameer Hamza]

Right now, this is the only way I can think of to detect even and odd numbers without using any rounding functions and just a while loop. I suspect there might be more efficient solutions.

A=[1; 2; 3; 4; 5; 6; 7; 8];

Evens = [];
Odds = [];
for i=1:numel(A)
    x = A(i);
    tf = isEven(x);
    if tf
        Evens = [Evens x];
    else
        Odds = [Odds x];
    end
end

function tf = isEven(x)
    x = abs(x);
    while true
        x = x - 2;
        if x == 0
            tf = 1;
            return
        elseif x < 1
            tf = 0;
            return
        end
    end
end