Generalized Forced Van Der Pol Oscillator Phase Plot

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Thomas Ward
Thomas Ward le 16 Avr 2020
Commenté : george korris le 15 Avr 2021
Hello,
I am trying to write a program to solve a forced van der pol oscillator and give its phase plot. I found a code on these forums, posted by @KSSV that solved an unforced van der pol oscillator and I just added a forcing term, and it worked. Here is the code
function VanderPol()
[t,y] = ode23(@vdp1,[0 20],[2; 0]);
plot(t,y(:,1),'-o',t,y(:,2),'-o')
title('Solution of van der Pol Equation (\mu = 1) with ODE23');
xlabel('Time t');
ylabel('Solution y');
legend('y_1','y_2')
figure
plot(y(:,1),y(:,2))
title('Phase plane plot')
end
function dydt = vdp1(t,y)
dydt = [y(2); 3*(1-y(1)^2)*y(2)-y(1)+8*sin(4*t)];
end
I was able to go in and play with the variables to obtain different results, which was great, but ideally I would want to generalize the code such that the second line read
[t,y] = ode23(@vdp1,[0 20],[idis; ivel]);
And the line prior to end read
dydt=[y(2); mu*(1-y(1)^2)*y(2)-y(1)+A*sin(omega*t)];
And then be able to call VanderPol(idis, idel, mu, A, omega) and be able to solve that without having to go in and manually change it each time

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Star Strider
Star Strider le 17 Avr 2020
Try this:
function [t,y] = VanderPol(idis, ivel, mu, A, omega)
[t,y] = ode23(@vdp1,[0 20],[2; 0]);
plot(t,y(:,1),'-o',t,y(:,2),'-o')
title('Solution of van der Pol Equation (\mu = 1) with ODE23');
xlabel('Time t');
ylabel('Solution y');
legend('y_1','y_2')
figure
plot(y(:,1),y(:,2))
title('Phase plane plot')
function dydt = vdp1(t,y)
dydt = [y(2); mu*(1-y(1)^2)*y(2)-y(1)+A*sin(omega*t)];
end
end
Then to call it:
idis = 2;
ivel = 0;
A = 8;
omega = 4;
mu = 3;
[t,y] = VanderPol(idis, ivel, mu, A, omega);
figure
plot(t,y)
grid
I added a tweak so that you can get the integrated results from your funciton. It is otherwise what you wrote.
.
  3 commentaires
Star Strider
Star Strider le 17 Avr 2020
As always, my pleasure!
george korris
george korris le 15 Avr 2021
hey guys is this code solving this equation: and what does: Solution of van der Pol Equation (\mu = 1) with ODE23' that the first figure has as title mean?

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