I have 3, 10 x 1 arrays. The first array is the x-position. The second array is the y-position. The third array is the indent depths as a function of the x and y positions. I want to create a 2D color plot with an X and Y axis and then the Z axis would be the different colors along the area of the x, y surface. Is there a way to do something like this? I want for different colors to represent different indent depths. I dont want this to be a 3D plot.
Thank you.

 Réponse acceptée

Star Strider
Star Strider le 25 Avr 2020

0 votes

Your problem statement appears to have eliminated most solutions.
Try this:
x = rand(10,1);
y = rand(10,1);
z = rand(10,1);
xv = linspace(min(x), max(x), numel(x));
yv = linspace(min(y), max(y), numel(y));
[X,Y] = ndgrid(xv, yv);
Z = griddata(x, y, z, X, Y);
figure
surf(X, Y, Z)
view(0,90)
% view(90,0)
It creates a 3D surface, then orients it with view to create a 2D plot.

4 commentaires

birdnerd007
birdnerd007 le 25 Avr 2020
@Star Strider - Thanks for your reply. This seems to be in the right direction....
Perhaps I explained it incorrectly, my apologies. There are 10 tests that happened. Each test represents and indent at a specific depth that took place at a certain x,y position. There is only 1 solution for each indent and I want to be able to represent by color the depth associated with that test. I don't know if that makes sense? The data is discrete.
My pleasure!
The scatter function may be more appropriate (assuming that I unserstand what you want):
x = rand(10,1);
y = rand(10,1);
z = rand(10,1);
figure
scatter(x, y, [], z, 'filled')
grid
Here, the ‘z’ value assigns the colour. (The third scatter argument sets the marker size. I set it to use the default value by passing the empty array [] in that position.) Experiment with different expressions for the colour argument to get the result you want.
birdnerd007
birdnerd007 le 25 Avr 2020
Perfect! Thanks a million!
Star Strider
Star Strider le 25 Avr 2020
As always, my pleasure!

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