inverce laplace and ploting data
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s = zpk('s')
Gs=(9)/(s^2+9*s+9);
pole(Gs)
zero(Gs)
Ct=ilaplace(Gs)
figure
plot(Ct)
2 commentaires
Rena Berman
le 1 Juin 2020
(Answers Dev) Restored edit
Star Strider
le 1 Juin 2020
Thank you.
Réponses (1)
Star Strider
le 16 Mai 2020
I believe that what you actually want is:
s = zpk('s')
Gs=(9)/(s^2+9*s+9);
pole(Gs)
zero(Gs)
% Ct=ilaplace(Gs)
figure
step(Gs)
since under other circumstances (specifically using the Symbolic Math Toolbox), plotting ilaplace of a symbolic transfer function (using fplot) would return the impulse response. To plot a symbolic step response, you would divide ‘Gs’ by ‘s’, then use fplot.
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