How to store index values in the form of arrays using for loop?

Hello Everyone

Can you please tell me how to save indes values of the following code from the for loop?

rng default
M = zeros(randi([3 6]),randi([3 6]))
[u,v] = size(M)
for i = 1:u
    for j = 1:v
       ind1(i) = i;
       ind2(j) = j;
       indices = [ind1(i),ind2(j)]
    end
end

I want to store the values in the form of two colums and m*n rows.

Thank you

Answer 1

[Sugar Daddy]

rng default
M = zeros(randi([3 6]),randi([3 6]))
[u,v] = size(M)
inc  =1;
for i = 1:u
    for j = 1:v
       indices(inc,:) = [i ,j];
       inc = inc+1;
    end
end

or you can use to ind2sub instead of for loop

[x,y]=ind2sub(size(M),1:numel(M));
indices = [y' x'];

Answer 2

[KALYAN ACHARJYA]

Cell array

rng default
M = zeros(randi([3 6]),randi([3 6]))
[u,v] = size(M)
indices=cell(u,v);
for i = 1:u
    for j = 1:v
       ind1(i) = i;
       ind2(j) = j;
       indices{i,j}=[ind1(i),ind2(j)];
    end
end

[SAURAV SANKHE]

Thank you Kalyan Acharjya.

Have a great day

[madhan ravi]

You don’t preallocate properly do you?