Month as a two digit number

I have

month(Date);

this will give me the number 1,2,3,...

But I want to have 01,02,03,.. as months. Please advise.

[dpb]

Output formatting is independent of value...need to know where you want this appearance to be.

If it's the Date itself, then set the .Format property.

[alpedhuez]

Eventually want to create yyyy-mm variable

yyyy_mm=strcat(num2str(year),'-',num2str(month));

and I want to have "month' as a two digit number so that output is like '2020-01'.

[dpb]

Hadn't seen this comment ere now--

Again, use the proper variable class for the purpose --

>> Date = datetime('now') % build the date variable -- how is up to your application
Date = 
  datetime
   03-Jul-2020 12:39:53
>> Date.Format='yyyy-MM' % set the desired display format--anything that uses will be as shown on output
Date = 
  datetime
   2020-07
>> string(Date)  % if you really must have a string or cellstr(), it's what you get automagically
ans = 
    "2020-07"
>> disp(Date)    % or just use the variable; its output format is as requested
   2020-07
>> 

As another poster noted, do NOT use month as a variable; that aliases the builtin month() function.

Answer 1

[Star Strider]

To have leading zeros, it has to be a character array or string variable.

Try this:

Date = datetime('now');
mth = sprintf('%02d',month(Date));

producing:

mth =
    '07'

.

[dpb]

Or...

Date.Format='MM';

which produces

>> disp(Date)
   07
>> 

[madhan ravi]

Date = datetime('now',"Format",'MM') % which is what i mean't in my comment ;)

[Star Strider]

I also didn’t see this Comment until now.

Expanding on my initial Answer:

Date = datetime('now')+calmonths(0:3).';
Date.Format = 'yyyy-MM';
Out = Date

produces:

Out = 

  4×1 datetime array

   2020-07
   2020-08
   2020-09
   2020-10

.

Answer 2

[madhan ravi]

ix = m < 10 % m is the output of the month(...) , by the way it can be set by Format in datetime(...)
M = "" + m
M(ix) = 0 + "" + m(ix)

[alpedhuez]

So suppose I have a 'month' variable. How will it work?

[dpb]

How will it work for what?

As said before, w/o any context we have no klew what you're trying to accomplish.

The display format is independent of the data; is it the output you're concerned about how it looks or something else?

[madhan ravi]

Replying to your comment in https://in.mathworks.com/matlabcentral/answers/558439-month-as-a-two-digit-number#comment_923660:

yyyy_mm = datetime("now","Format","uuuu-MM")

Replying to your comment in https://in.mathworks.com/matlabcentral/answers/558439-month-as-a-two-digit-number#comment_923603

m = randi([1, 12], 10, 1); % months example
ix = m < 10 ; 
M = "" + m;
M(ix) = 0 + "" + m(ix) 

Note: Naming a variable month is a terrible idea!!!

[alpedhuez]

Let me work on it.