Removing time from datetime

Hi,

I have a datetime array in the following format i.e. 31-Dec-2019 08:00:00. I just want to remove the time component from the datetime so that I get 31-Dec-2019. Any ideas

Answer 1

[Steven Lord]

If you want to change how it is displayed, change the Format property.

>> dt = datetime('now')
dt = 

  datetime

   23-Aug-2020 15:43:06

>> dt.Format = 'dd-MMM-yyyy'

dt = 

  datetime

   23-Aug-2020

If you want to change what's stored and used for calculation, dateshift the datetime to the start of the day.

>> dt2 = dateshift(dt, 'start', 'day');
>> dt - dt2

ans = 

  duration

   15:43:06

Answer 2

[Star Strider]

Try this:

dt = '31-Dec-2019 08:00:00';
Out = datetime(dt, 'InputFormat','dd-MMM-yyyy HH:mm:ss', 'Format','dd-MMM-yyyy')

producing:

Out = 

  datetime

   31-Dec-2019

.