Add an element if string meets conditions

A = ["tennis", "pizza", "switch", "popcorn", "laptop", "cupboard"];
word = "lookie"

for i=1:length(A)
    if xxxx
        str = append(A,word)
    end
end

My desired result would be for every word that starts with a 'p', append "lookie".

so the output would be

[tennis pizzalookie switch popcornlookie laptop cupboard]

How can I do this would a loop? I tried using startWith but when I set the condition, lookie is appended to all the words not just the ones I want.

Answer 1

[Star Strider]

This seems to be homework, however it’s nevertheless an interesting problem.

Try this:

A = ["tennis", "pizza", "switch", "popcorn", "laptop", "cupboard"];
word = "lookie";
Idx = startsWith(A, "p");
Out = A;
Out(Idx) = append(A(Idx),word)

producing:

Out = 

  1×6 string array

    "tennis"    "pizzalookie"    "switch"    "popcornlookie"    "laptop"    "cupboard"

This requires R2019b or later.

EDIT — Corrected typographical error.

[Karen Landeros]

Thank you so much! Don't worry it's not homework. Just a question I had since I make up random problems for myself to help me since coding in general is not my forte (yet? :0).

[Star Strider]

My pleasure!

If my Answer helped you solve your problem, please Accept it!

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