Effacer les filtres
Effacer les filtres

polyfit semilogy

5 vues (au cours des 30 derniers jours)
Nicolas
Nicolas le 21 Avr 2011
Hi,
I'm trying to find the fractal dimension of a range of data, but I'm sruggling looking for a way of finding the best range of data in a bigget set of data, which will fit the best regression line in semilog.
do i have to try every possibilitie,
A=polyfit(X(1:1000),log10(Y(1:1000),1);
A=polyfit(X(2:1000),log10(Y(2:1000),1);
...
A=polyfit(X(i:j),log10(Y(i:j)),1);
and so on.. or is there easiest way?
Thank you for your help
n.
  2 commentaires
Andrew Newell
Andrew Newell le 22 Avr 2011
What are X and Y?
Nicolas
Nicolas le 24 Avr 2011
for example
X= 1500:500:7000
Y= 4 15 30 59 96 151 214 291 380 480 598 741
I've tried to take out the points with the highest residuals, but it doesn't work very well. I need to truncate my data from the ends towards the middle to find the best fit, instead of taking out the middle point to make the regression line better.

Connectez-vous pour commenter.

Réponses (2)

bym
bym le 21 Avr 2011
do you mean stepwise regression?
doc stepwise() % assuming you have statistics toolbox
  1 commentaire
Nicolas
Nicolas le 22 Avr 2011
hi, do you think stepwisefit would be better in my case?
I'll work on that, both sounds interesting ways!

Connectez-vous pour commenter.


Andrew Newell
Andrew Newell le 22 Avr 2011
If X vs Y is a box count plot, you could calculate a local scaling exponent.

Catégories

En savoir plus sur Fractals dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by