How can I use a string in legend()?

I have the following string:

Now I want to use this string to produce a legend to my figure. So I use

and get this:

But I would like to have this,

which I got by using the following command:

Tthis is exactly the string Legend copied into the function legend().

How can I use directly the string Legend, without copying it to the function legend()?

Edit: I forgot the following code sniplet:

p=zeros(2*length(HG),1);
hold on;
for iter2 = 1:length(HG)
  p(2*iter2-1)=plot(freq,real(n(:,iter2)), 'color', cc(iter2,:));   
  p(2*iter2)= plot(freq,imag(n(:,iter2)),'--', 'color', cc(iter2,:));  
end

I use the variable p to skip all dotted lines in the legend.

[Ameer Hamza]

Why do you want to use the first syntax? It is not supported in MATLAB. The second syntax is the correct MATLAB's way of drawing the legends.

[Marcel345614]

Because I build the Legend-string and want to use it now. This is how I build it:

values=1:2:(2*length(HG)); %only the solid line should have a legend
Legend1=strcat('[',sprintf('p(%d) ',values),']',',');
Legend2=cell(length(HG),1);
quote=char(39);
for iter3=1:length(HG)
    if iter3<length(HG)
        Legend2{iter3}=strcat(quote,'HS+HG=', num2str(HS(iter3)),'+',num2str(HG(iter3)),quote,',');
    else
        Legend2{iter3}=strcat(quote,'HS+HG=', num2str(HS(iter3)),'+',num2str(HG(iter3)),quote);
    end
end
Legend3=string(strjoin(Legend2));
Legend=strcat(Legend1,'{',Legend3,'}');

[Walter Roberson]

http://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Answer 1

[Ameer Hamza]

Although Walter's comment already shows the problems with eval(), in case you still want to use the current method, then the closest you can get is something like this

fig = figure()
hold on
p(1) = plot(rand(1,10))
p(2) = plot(rand(1,10))

Legend_str1 = "[p(1) p(2)]";
Legend_str2 = "{'ABC', 'DEF'}";
legend(eval(Legend_str1), eval(Legend_str2))

Answer 2

[Alan Stevens]

You could use

Legend = ['HS+HG = 0.5+5' ;'HS+HG =   1+5'];
legend(Legend)

But make sure there are the same number of characters (including spaces) in both strings.

[Ameer Hamza]

Following alternatives does not require that character arrays have equal lengths.

Legend = {'HS+HG=0.5+5';'HS+HG=1+5'};
legend(Legend)

or

Legend = ["HS+HG=0.5+5";"HS+HG=1+5"];
legend(Legend)

[Penghao Duan]

Thanks, that is helpful