Numerical integration in MATLAB

1 vue (au cours des 30 derniers jours)
Raj Patel
Raj Patel le 27 Oct 2020
Commenté : Star Strider le 27 Oct 2020
Hello everyone,
I am trying to first numerically integrate a function and then plot the output of the integral. However, I have a variable T which is in the range (1:1000). I am not sure how to use a loop in integral and then plot values for all T with the corresponding value of integral. The MATLAB code is:
Hello everyone,
I am trying to first numerically integrate a function and then plot the output of the integral. However, I have a variable T in the integral which is in the range (1:1000). I am not sure how to use a loop in integral and then plot values for all T with the corresponding value of integral. The MATLAB code is:
kb = 1.38 .* 10.^-23;
h = 1.05 .* 10.^-34;
wd = 6.94 .* 10.^13;
vs = 6084;
B1 = 2.7 .* 10.^-19;
B2 = 170;
A1 = 2 .* 10.^-45;
D = 0.004;
T = 300;
c = (h.^2 .* D) ./ (2 .* pi * pi * vs * kb .* T .* T);
T = 1:1000;
fun = @(x) ((x.^4 .* exp((h.*x) ./ (kb .* T))) ./ (((exp((h.*x) ./ (kb .* T))-1).^2) .* ((D.*B1 .* x.^2 .* T .* exp(-B2/T)) + (D.*A1 .* x.^4) + vs)));
K = c .* integral(fun,0,wd)
plot(T, K)
Thanks in advance,
Raj Patel.
  1 commentaire
Raj Patel
Raj Patel le 27 Oct 2020
The code is:
(Note: I removed a line where T was defined 2nd time)
Thanks in advance,
Raj Patel.
kb = 1.38 .* 10.^-23;
h = 1.05 .* 10.^-34;
wd = 6.94 .* 10.^13;
vs = 6084;
B1 = 2.7 .* 10.^-19;
B2 = 170;
A1 = 2 .* 10.^-45;
D = 0.004;
c = (h.^2 .* D) ./ (2 .* pi * pi * vs * kb .* T .* T);
T = 1:1000;
fun = @(x) ((x.^4 .* exp((h.*x) ./ (kb .* T))) ./ (((exp((h.*x) ./ (kb .* T))-1).^2) .* ((D.*B1 .* x.^2 .* T .* exp(-B2/T)) + (D.*A1 .* x.^4) + vs)));
K = c .* integral(fun,0,wd)
plot(T, K)

Connectez-vous pour commenter.

Réponse acceptée

Star Strider
Star Strider le 27 Oct 2020
Try this:
c = @(T) (h.^2 .* D) ./ (2 .* pi * pi * vs * kb .* T .* T);
fun = @(x,T) ((x.^4 .* exp((h.*x) ./ (kb .* T))) ./ (((exp((h.*x) ./ (kb .* T))-1).^2) .* ((D.*B1 .* x.^2 .* T .* exp(-B2/T)) + (D.*A1 .* x.^4) + vs)));
T = 1:1000;for k = 1:numel(T)
K(k) = c(T(k)) .* integral(@(x)fun(x,T(k)),0,wd);
end
figure
plot(T, K)
grid
xlabel('T')
ylabel('K')
producing:
Since both ‘c’ and ‘fun’ are functions of ‘T’, they need to be coded as such.
  4 commentaires
Raj Patel
Raj Patel le 27 Oct 2020
Oh! I see.
Thanks,
Raj Patel.
Star Strider
Star Strider le 27 Oct 2020
As always, my pleasure!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Graphics Performance dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by