contour plot of stream function for a tornado

I have a stream function for a tornado and I watned to plot it using contour function, but it's not working:
m1=-3000;
m2 = 5800;%strength
[r,theta] = meshgrid(-20:1:20,0:0.1:2*pi);
psi = (m1/(2*pi))*theta + (m2/(2*pi))*log(r);
contour(r,theta,psi);
How should I fix it so the plot looks something like this:
I also want to plot a circle in the middle with radius r = a constant value

 Réponse acceptée

More like this?
m1=-3000;
m2 = 5800;%strength
R = 0:0.1:20;
THETA = linspace(0,2*pi,numel(R));
[r,theta] = meshgrid(R,THETA);
psi = m1/(2*pi)*theta + (m2/(2*pi))*log(r);
contour(r.*cos(theta),r.*sin(theta),psi,20,'b--');

2 commentaires

Randy Chen
Randy Chen le 28 Oct 2020
yes that's great!
by the way how should I add a circle with a constant radius? should I still use contour? i'm not sure how to do that
Alan Stevens
Alan Stevens le 28 Oct 2020
Modifié(e) : Alan Stevens le 29 Oct 2020
Like so
m1=-3000;
m2 = 5800;%strength
R = 0:0.1:20;
THETA = linspace(0,2*pi,numel(R));
[r,theta] = meshgrid(R,THETA);
psi = m1/(2*pi)*theta + (m2/(2*pi))*log(r);
contour(r.*cos(theta),r.*sin(theta),psi,20,'b--');
hold on
rc = 10;
plot(rc*cos(THETA), rc*sin(THETA),'k')
axis equal

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Contour Plots dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by