Réponses (1)

Star Strider
Star Strider le 22 Nov 2020

3 votes

It depends on the curve and how you define it.
Example —
x = linspace(-5, 5);
y = x.^2-2;
zx = find(diff(sign(y)));
for k = 1:numel(zx)
xint(k) = interp1(y(zx(k)+[-1 1]), x(zx(k)+[-1 1]), 0);
end
figure
plot(x, y)
hold on
plot(xint, zeros(size(xint)), 'p')
hold off
grid
.

2 commentaires

Steven
Steven le 4 Déc 2022
This worked perfectly for my equation thank you
Star Strider
Star Strider le 5 Déc 2022
My pleasure!

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