binary to decimal conversion.......need ans immidiately plzzzzzzzzzzz

hello! I have a string of binary suppose a binary string of 2000 bit. A=[0 0 0 0 1 1 0 1 1 0 1 0 0 ............so on] I wana to convert it into decimals. though i use function B=bin2dec(A, 8). but it returns me error. i wana to convert each 8-bits into decimal number. plz help me how should i do it. Thanks

Answer 1

[Teja Muppirala]

sum(bsxfun(@times,reshape(A,8,[]), 2.^(7:-1:0)'))

[Andrei Bobrov]

or

reshape(A,8,[])'*2.^(7:-1:0)'

[Teja Muppirala]

Good catch. Much better.

[Teja Muppirala]

Same without transposes:

2.^(7:-1:0)*reshape(A,8,[])

Answer 2

[RoJo]

bin2dec takes a binary string as input argument.

So you can convert A into 8 bit strings and then call bin2dec

For example A1 = '00001101' B1 = bin2dec(A1)

Answer 3

[Andrei Bobrov]

variant

bin2dec(num2str(reshape([A,zeros(1,8-rem(length(A),8))],[],8)))

[Walter Roberson]

bin2dec(char('0'+reshape([A,zeros(1,8-rem(length(A),8))],[],8)))