Extract partial data from datetime using logics/vectorization
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Stefan555
le 18 Déc 2020
Réponse apportée : Eric Sofen
le 5 Jan 2021
Say I have some datetime data:
rowMin =
20×1 datetime array
02-Nov-2020 09:00:00
03-Nov-2020 09:10:00
04-Nov-2020 09:00:00
05-Nov-2020 09:14:59
06-Nov-2020 09:59:59
09-Nov-2020 09:05:00
10-Nov-2020 09:00:00
11-Nov-2020 09:35:00
12-Nov-2020 13:15:00
13-Nov-2020 09:00:00
16-Nov-2020 09:00:00
17-Nov-2020 15:00:00
18-Nov-2020 09:35:00
19-Nov-2020 10:15:00
20-Nov-2020 14:10:00
23-Nov-2020 16:35:00
24-Nov-2020 09:00:00
25-Nov-2020 11:15:00
26-Nov-2020 09:00:00
27-Nov-2020 10:20:00
where I wish to separate different weekdays (always Monday to Friday):
DayNumber=weekday(rowMin);
and then to extract hours and minutes for, respectively, Mondays, Tuesday, ..., Fridays, for subsequent analysis.
How to do this - preferably using logics and vectorization?
My first attempt:
MondayH=zeros(length(rowMin),1); % preallocation
MondayM=zeros(length(rowMin),1); % preallocation
for ii=1:length(rowMin)
if DayNumber(ii,1)==2 % Monday
[MondayH(ii,1),MondayM(ii,1),~]=hms(rowMin(ii,1));
end
end
Bonus info: I would like to utilize dur (duration) on the resulting array so that I afterwards can identify mean HH:mm of the individual days.
0 commentaires
Réponse acceptée
Eric Sofen
le 5 Jan 2021
I would extract the time components first and then deal with grouping by day of the week. It's easy to keep this all organized in a table:
d = datetime(2021,1,1) + minutes(randi([0,10000],[100,1])); % cook up some data
d = sort(d);
t = table(d);
t.dow = weekday(d);
t.hour = hour(d);
t.min = minute(d);
% Get the hours for Tuesday (use {} to get results as an array, () as a table)
t{t.dow == 3, "hour"}
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Dates and Time dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!