to find co-cordinate of Intersection point of line?
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x=[7.8 8.25 8.5];
y=[0.96 0.99 0.94];
p=polyfit(x,y,2);
f=polyval(p,x);
plot(x,y,'o',x,f,'-');
hold on;
line([7.8 8.5],[0.96 0.94]);
hold on;
line([8.25 8.25],[0 0.99]);
Now want to compute intersection point of both lines?
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Walter Roberson
le 4 Avr 2013
p1 = polyfit(x(1:2), y(1:2), 2);
b1 = polyval(p1, 0);
m1 = polyval(p1, 1) - b1;
p2 = polyfit(x(2:3), y(2:3), 2);
b2 = polyval(p2, 0);
m2 = polyval(p1, 1) - b2;
And now you have m1*x + b1 = m2*x + b2, so m1 * x - m2*x = b2 - b1, so (m1 - m2) * x = b2 - b1, and so x = (b2 - b1) / (m1 - m2), after which y = m1*x + b1 to find the corresponding y.
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