Adding values to cells as the indices increase

Hi!

I have a n x m cell array and i want to add a multiple of a constant as n and m increases.

(1,1) (1,2) (1,3)

(2,1) (2,2) (2,3) ---- add constant to row nr 2.

(3,1) (3,2) (3,3) ---- add constant x2 to row nr 3.

I would also like to add a constant to columns as they increase.

Any suggestions?

[KALYAN ACHARJYA]

Can you elaborate the question again (please be clear and make it simple)?

[Holmbrero]

I'll try to elaborate.

(1,1) (1,2) (1,3)

(2,1) (2,2) (2,3)

(3,1) (3,2) (3,3)

I want to add a constant to row nr 2 ((2,1) (2,2) (2,3) ) and a multiple of the same constant to row nr 3 ((3,1) (3,2) (3,3) )

I also want to add another constant to column nr 1 ((1,2) (2,2) (2,3)) and a multiple of the same constant to columnt 3 ((1,3) (2,3) (3,3)).

I could just add them manually but i need the solution to work on a arbitrary nxm cell array.

Did that make my question easier to interpret?

Regards

[Aaron Fredrick]

Yes I understand your question but, just to blear could you tell as the matrix increases each time,

a constant is added to 2nd row and a multiple of that to the 3rd row, and another constant to 1st column and a multiple of that to the 3rd column

OR

a constant is added to 2nd row and a multiple of that to the last row, and another constant to 1st column and a multiple of that to the last column

And, is the the multiplication of the constant is same for each time?

Answer 1

[Gaurav Garg]

Hi Holmbrero,

I understand that you wish to add multiples of constants to each row. I am providing with a pseudo-code to help you do that -

for i=1:size(c,1)
    for j=1:size(c,2)
        c{i,j} = c{i,j} + constant * i
    end
end

Assuming that 'c' is your cell array, the above code would add each cell element with a constant, depending on the row number.

You can similarly replicate the code to add each element with constant, depending on column number, like this -

for i=1:size(c,1)
    for j=1:size(c,2)
        c{i,j} = c{i,j} + constant * j
    end
end

[Holmbrero]

Hi!

Sorry for my late reply.

I solved it by creating two new matrices with the added constants and then simply added these to the cell array.

The problem was somehow sort of hard to describe but i think your solution is also appliciable.

Thank you for your help!