Counting coins - bwconncomp returns only one object
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I'm doing an exercise using the Image Processing Toolbox and the 'coins.png' image built-in in MATLAB.
In the last line of the code before the function, when I call the function bwconncomp, I returns only one object instead of 14.
filtsize = 85;
im1 = imread('coins.png');
[r,c] = size(im1);
im2 = imread('eight.tif');
[r2,c2] = size(im2);
filtsizeh = floor(filtsize/2);
im = zeros(r+r2+filtsize,c+filtsize);
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
[r,c] = size(im);
imagesc(im);colormap(gray);title('test image');axis equal;
msk=[]; msk_dil=[]; msk_dil_erd=[]; centroid=[]; component_size=[];
[msk,thrsh] = OtsuThreshold(im);
figure; imagesc(msk); colormap(gray); title('Otsu'); axis equal;
msk_dil = im<=88;
figure; imagesc(msk_dil); colormap(gray); title('Dilated'); axis equal;
msk_dil_erd = imerode(msk_dil,ones(7,7));
figure; imagesc(msk_dil_erd); colormap(gray); title('Eroded'); axis equal;
comps = bwconncomp(msk_dil_erd);
%%
function [msk,thrsh] = OtsuThreshold(img)
histogram = imhist(img);
thrsh = otsuthresh(histogram);
thrsh = thrsh*255;
msk = img > thrsh;
end


Someone able to help?
Réponse acceptée
Plus de réponses (1)
Image Analyst
le 24 Déc 2020
So it doesn't work because of this line:
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
c is the number of columns in im1, then you're trying to use it to index into im2, which does not have as many columns as im1, and it throws the error.
Index in position 2 exceeds array bounds (must not exceed 308).
Error in test5 (line 17)
im(filtsizeh+1:filtsizeh+r+r2,filtsizeh+1:filtsizeh+c) = [im1;255-im2(:,1:c)];
But I noticed you accepted the answer so I guess you got it figured out. Let us know if that's not the case and I need to fix anything.
2 commentaires
KALYAN ACHARJYA
le 24 Déc 2020
Sir, I executed the code, it runs without any error. (Considering the same image name)
Image Analyst
le 24 Déc 2020
Yes, but if they're different sized images like he used, then it throws an error.
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