How to solve this equation?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi. I want to solve this equation (find the root of this polynomial).
How can I do that?
h^0.66+0.0805*h=0.045
0 commentaires
Réponses (2)
David Hill
le 24 Fév 2021
Modifié(e) : David Hill
le 24 Fév 2021
f=@(h)h.^0.66+0.0805*h-0.045;
fzero(f,0.008);%plot(0:.001:.1,f(0:.001:.1)) to get approximate location to root
0 commentaires
Star Strider
le 24 Fév 2021
Probably the easiest approach:
syms h z2
Eqn = h^0.66+0.0805*h == 0.045;
[h,prms,cndx] = solve(Eqn,h, 'ReturnConditions',1)
vpa_cndx = vpasolve(z2^50 + (2000*z2^33)/161 - 90/161 == 0); % Returns All 50 Roots
.
0 commentaires
Voir également
Catégories
En savoir plus sur Calculus dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!