Eigen Vectors and Values using Matlab

I'm using the following code to find the eigen vectors, now when I evaluate lambda manually I get dfferent numbers

A=[4 6 2;6 0 3;2 3 -1];
[lambda]=eig(A)
lambda=round(lambda,2);
L=length(lambda)
E1=rref(A - lambda(1)*eye(L),1e-14)
E2=rref(A - lambda(2)*eye(L),1e-14)
E3=rref(A - lambda(3)*eye(L),1e-14)

But I'm getting the trivial solution while I shouldn't

Answer 1

[Bjorn Gustavsson]

Why not calculating the eigenvectors at once?

[Ev,lambda]=eig(A)

Also, when rounding the eigenvalues, you're no longer guaranteed to work with the eigenvalues - then the trivial solution is most likely the only solution.

HTH

Answer 2

[KSSV]

A=[4 6 2;6 0 3;2 3 -1];
lambda=eig(A) 

syms l 
eqn = det(A-l*eye(3))==0 ;
solve(eqn,l) ;
l = double(vpasolve(eqn,l)) 

[Diana]

What about the eigen vectors why rref() is giving me the trivial solution

[KSSV]

[v,d,w]=eig(A)