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Fit with an integral involved
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Daniele Sonaglioni
le 3 Mar 2021
Commenté : Star Strider
le 3 Mar 2021
Hi everybody,
i have some problem in fitting my experimental data with a function involving an integral in it.
My fitting function is the subsequent:
where
and
where E1,E2,T^* and T^' are my fitting parameters, while T is my abscissa.
I have tried defining a unique function in lsqcurvefit but it does not work. I have some difficulties in defining the integral in the fitting function.
Can someone help me with the code?
Thaks a lot.
3 commentaires
Réponse acceptée
Star Strider
le 3 Mar 2021
Try this:
function y = integralfit(b,Tv,R,nu,T0)
% % % MAPPING: b(1) = E1, b(2) = E2, b(3) = Tstar, b(4) = Tdot
for k = 1:numel(Tv)
k3 = @(T) exp(-b(2).*(1./T - 1./b(3))./R);
K = @(T) exp(-b(1).*(1./T - 1./b(4))./R);
y(k) = (b(1)/nu) .* k3(Tv(k)).* K(Tv(k)) .* exp(-(1./nu).*integral(@(T) k3(T).*K(T), T0, Tv(k), 'ArrayValued',1));
end
end
T = 1:10; % Use Actual Vector
y = rand(size(T)); % Use Actual Vector
R = 9; % Use Actual Value
nu = 7; % Use Actual Value
T0 = T(1); % Use Actual Value
B = lsqcurvefit(@(b,T)integralfit(b,T,R,nu,T0), rand(4,1), T, y)
figure
plot(T, y, 'p')
hold on
plot(T, integralfit(B,T,R,nu,T0), '-r')
hold off
grid
It runs without error and appears to produce appropriate results on a random vector and random extra parameters. I obviously cannot test it with your data to see if it is producing appropriate parameter estimates.
It is somewhat slow because of the loop, however there is no way to correct for that since ‘T’ is the upper limit of integration, and that must be a scalar for integral to work correctly.
Remember to save the ‘integralfit’ function as integralfit.m on your MATLAB search path before you use it.
7 commentaires
Star Strider
le 3 Mar 2021
As always, my pleasure!
I am glad that you were able to estimate the parameters correctly, since they eluded me, even using the genetic algorithm.
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