Fluid Pathline using Euler's Method with MATLAB

4 vues (au cours des 30 derniers jours)
Kristjan Gjata
Kristjan Gjata le 20 Mar 2021
Modifié(e) : Alan Stevens le 21 Mar 2021
Hello.
I'm trying solve a problem of my course lecture in Fluid Mechanics.
We have velocity: u = y^2 - x^2 + t^2 at X-direction and v= 2xy + 20t at Y-direction.
To find the pathline of fluid we have the initial conditions that x0=1.5, y0=1 and t0=0 and we should use Euler's Method to determine the function.
I use the step of 0.001 for the time variable until t(final) = 10.
The problem in below program is debugging. Can someone help me ?
clear all
clc
f=@(x,y,t)y^2-x*2+t^2;
g=@(x,y,t)2*x*y + 20*t;
x0=input('\n Enter initial value of x i.e. x0: ');
y0=input('\n Enter initial value of y i.e. y0: ');
t0=input('\n Enter initial value of t i.e. t0: ');
tn=input('\n Enter the final value of t: ');
h=input('\n Enter the step length h: '); %example h=0.001
%Formula: y1=y0+h*function(x0,y0,t0);
fprintf('\n t x y');
while t0<=tn
fprintf('\n%4.3f %4.3f %4.3g',t0,x0,y0); %values of t and x and y
x1=x0+h*f(x0,y0,t0);
y1=y0+h*g(x0,y0,t0);
t1=t0+h;
x0=x1;
y0=y1;
end
Thank you very much.

Réponse acceptée

Alan Stevens
Alan Stevens le 21 Mar 2021
Modifié(e) : Alan Stevens le 21 Mar 2021
Replace
t1=t0+h;
by
t0=t0+h;
or add a line
t0 = t1;

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