plot to the function

20 vues (au cours des 30 derniers jours)
Junway
Junway le 9 Avr 2021
Réponse apportée : DGM le 9 Avr 2021
This is function
when r 0 to 3
when z 0, 0.03, 0.2, 0.5, 1,2
can you help me plot?
do i use vector or for loop or calculate each part and put in matlab?

Réponse acceptée

KALYAN ACHARJYA
KALYAN ACHARJYA le 9 Avr 2021
Modifié(e) : KALYAN ACHARJYA le 9 Avr 2021
Hint:
z=[0, 0.03, 0.2, 0.5, 1,2];
r=0:0.01:3;
for i=1:length(z)
eq=..... % Here z(i)
plot(eq); % r vs. eq
hold on;
end
Add legend for z values

Plus de réponses (1)

DGM
DGM le 9 Avr 2021
If you're using a relatively new version, this should work. Avoid loops where possible. In this case, you don't need any.
r = linspace(0,3,20); % use a fine vector for this one
z = [0 0.03 0.2 0.5 1 2]'; % salient values, but transposed
% now we are doing elementwise math with row and col vectors
% our solution is now no longer a vector
% each row of f corresponds to one value of z
% note that doing this directly only works in R2016b or newer
% this could otherwise be done using a loop or bsxfun()
f = r.^2.*sqrt(1+(2*z.*r).^2) ./ sqrt((1+r.^2).^2 + (2*z.*r).^2);
clf
h = plot(r,f); grid on
% in order to get the zeta values in the legend automatically
aa=num2cell(z);
tagfun=@(x) sprintf('\\zeta = %2.2f',x)
legend(h,cellfun(tagfun,aa,'UniformOutput',false),'location','northwest')
xlabel('tony the tiger''s favorite letter')
ylabel('cereal consumed')

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by