how to set 1000 separator for large numbers in GUI MATLAB
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Hello! I am trying to find a way to set 1000 separator for the large numbers displayed in my GUI. For example: I would like the number 100000 to be displayed in my GUI like 100.000 or 100,000.
How could I do it? Thank you, in advance!
1 commentaire
Juan Saenz-Diez
le 18 Mai 2020
Hello! I wonder if this is what Natalia was asking, and whether she got her answer. What I would like to do is what I think Natalia is asking: how to get Matlab to display "normal" numbers with 1000 separators automatically, not in our own code output. Like doing "format bank" but adding the ',' separator to the thousands (as any banking application would do, which is the goal). Anyway, that is what I am looking for. Thanks for helping!
Réponses (4)
Teja Muppirala
le 24 Mai 2011
import java.text.*
v = DecimalFormat;
in = 123456789;
out = char(v.format(in))
Taken from here:
0 commentaires
Jan
le 24 Mai 2011
Without Java:
S = sprintf('%.16g', pi * 1e12); % [EDITED: was '%16']
T(1:length(S)) = char(0);
T(strfind(S, '.') - 4:-3:1) = char(39); % [EDITED: -3 -> -4]
S = [S; T];
S = reshape(S(S ~= 0), 1, []);
>> 3'141'592'653'589.793
3 commentaires
adams13
le 3 Mar 2023
Modifié(e) : adams13
le 8 Mar 2023
There is a small bug in this solution. For the integer value, it will not add any thousend separators.
strfind(S, '.')
will produce an empty array.
One can replace the line by
dotPos = strfind(S, '.');
if isempty(dotPos)
dotPos = length(S) + 1;
end
T(dotPos - 4:-3:1) = char(39); % [EDITED: -3 -> -4]
or even better
T(find([S '.'] == '.', 1) - 4:-3:1) = char(39); % [EDITED: -3 -> -4, strfind -> find([... '.'],1)]
Otherwise the solution is charming ;-)
Oleg Komarov
le 24 Mai 2011
Another alternative w/o java:
n = pi * 1e12;
c = fix(log10(n)+1);
dec = 3;
fmt = [repmat('%c',1,mod(c,dec)) repmat('''%c%c%c',1,fix(c/dec)) '%s'];
sprintf(fmt, sprintf('%.3f',n))
ans =
3'141'592'653'589.793
0 commentaires
Matt Fig
le 24 Mai 2011
Another alternative.
H = '123456.09'; % A string number.
S = regexp(H,'\.','split');
S{1} = fliplr(regexprep(fliplr(S{1}),'\d{3}(?=\d)', '$0,'));
H2 = [S{1},'.',S{2}]
Note that if H will never have a decimal amount, this becomes a simple one-liner. In this case,
H = '123456'; % A string number with no decimal point.
H2 = fliplr(regexprep(fliplr(H),'\d{3}(?=\d)', '$0,'))
3 commentaires
Matt Fig
le 25 Mai 2011
Nice Oleg, I looked for that but couldn't find it. Great work!
That lazy quantifier is a miracle worker, I need to spend more time with it.
Dominique
le 29 Août 2023
Modifié(e) : Dominique
le 29 Août 2023
It seems to me that this method works ideally when H is char array.
If the numericals were stored in a string array, then mind converting string to char .
example: table height is 62500
H = string(height(my_table)); % string var
H2 = fliplr(regexprep(fliplr(H),'\d{3}(?=\d)', '$0,')) % returns: 625,00 -> misleading
H = char(H) % char var
H2 = fliplr(regexprep(fliplr(H),'\d{3}(?=\d)', '$0,')) % returns: 62,500 -> expected
H2 = fliplr(regexprep(fliplr(H),'\d{3}(?=\d)', '$0 ')) % returns: 62 500 -> blank space separator
% ! Note:
H = char(height(my_table)); % may lead you to trouble
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