All possible combination based on 2^n
8 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I want to create a matrix containing all possible combination. Example of this is shown below. The size of the matrix depends on the number of variable n and the total of combination should follow the . The example below is valid for and, hence, the total number of rows is 8. The value of each element is 0 and 1.
How to create this matrix automatically depending on the number of variable n?
0 commentaires
Réponse acceptée
Plus de réponses (3)
Dyuman Joshi
le 14 Mai 2021
y = flipud(dec2bin(0:2^n-1,n))-'0' %method 1
y = dec2bin(2^n-1:-1:0,n)-'0' %method 2
Choose any of the methods you wish, both give the same result.
P.S - There is a similar question in Cody as well.
2 commentaires
Bjorn Gustavsson
le 14 Mai 2021
You could use dec2bin:
allpossibles = dec2bin(0:(2^n-1));
You'll have to extract the indices from the columns but that should be "not hard". There's more than likely many prettier solutions, for example have a look on the file exchange for nextperm (by Jos) and next-combination-permutation (by Matt-Fig).
HTH
0 commentaires
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!