Finding a range of data greater than 0.1

I have a range of data, for example like this
X = [ 0.02 0.17 0.32 0.28 0.04 -0.07 -0.01 -0.19 -0.45 -0.49 0.01 0.05 0.11 0.18 0.48 1.14 1.43 1.78 2.3 1.6 1.0 -0.1 0.1 0-2]
I want to find a range of X that all values in that range are greater than 0.1. I use this: find((X >= .1) ,1,'first') and find(X >= .1) ,1,'last')
but all data in that range are not greather than 0.1. And at last I want to find the longest range that has values more than 0.1.
In this example the answer is [0.11 0.18 0.48 1.14 1.43 1.78 2.3 1.6 1.0]

 Réponse acceptée

Alan Stevens
Alan Stevens le 18 Juin 2021
Modifié(e) : Alan Stevens le 18 Juin 2021
There must be a neater way, but the following might help:
X = [ 0.02 0.17 0.32 0.28 0.04 -0.07 -0.01 -0.19 -0.45 ...
-0.49 0.01 0.05 0.11 0.18 0.48 1.14 1.43 1.78 2.3 ...
1.6 1.0 -0.1 0.1 0-2];
Xptr = 0; Yptr = 1; row = 1;
while Xptr<numel(X)
Xptr = Xptr+1;
if X(Xptr)>0.1
Y(row,Yptr)=X(Xptr);
Yptr = Yptr+1;
elseif Xptr>1
row = row+1;
Yptr = 1;
end
end
XXptr = 1;
[r, c] = size(Y);
for i = 1:r
if Y(i,1)>0
XX(XXptr,:) = Y(i,:);
XXptr = XXptr+1;
end
end
disp(XX)
0.1700 0.3200 0.2800 0 0 0 0 0 0 0.1100 0.1800 0.4800 1.1400 1.4300 1.7800 2.3000 1.6000 1.0000

3 commentaires

Sahar khalili
Sahar khalili le 18 Juin 2021
Thank you so much. It works. And is there anyway to point out to the row of these values in the X?
The following will pick out the starting column numbers
find(X==XX(1,1))
find(X==XX(2,1))
Sahar khalili
Sahar khalili le 18 Juin 2021
I do appreciate it.

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