To find integral of a function in loop
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Nadia jabeen
le 6 Juil 2021
Commenté : Alan Stevens
le 6 Juil 2021
Hi,
I am calculating integral of a function 'f' with respect to lamda. I want to calculate variable 'q' for all possible values given in range of variable 'x'. upper limit and lower limit of variable lamda is as same as in variable 'x'. But matlab function given an error. kingly ghide me. or matlab show output of a single value. I want to do these calculations as a vector.
x = [600*10^-9:5*10^-9:800*10^-9];
for i = 1:numel(x)
N=(15.*z.*T*((h.*c).^3));
f=@(lamda)((Pi.^4).*(lamda.^4)*(k.^3));
q = integral(f,6e-7, x);
F=(N./q);
end
0 commentaires
Réponse acceptée
Alan Stevens
le 6 Juil 2021
Try replacing
q = integral(f,6e-7, x);
with
q(i) = integral(f,6e-7, x(i));
2 commentaires
Alan Stevens
le 6 Juil 2021
q holds all the results! For example:
x = [600*10^-9:5*10^-9:800*10^-9];
% Arbitrary data - replace with your own
N=1; %(15.*z.*T*((h.*c).^3));
k = 10^3;
lambda = 10^4;
f=@(lamda)((pi.^4).*(lamda.^4)*(k.^3));
for i = 1:numel(x)
q(i) = integral(f,6e-7, x(i));
F=(N./q);
end
plot(x,q),grid
xlabel('x'),ylabel('q')
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Global or Multiple Starting Point Search dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!