How read Matrix Market data into MATLAB?
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Hello. I'd like to read matrix data from the following link: https://morwiki.mpi-magdeburg.mpg.de/morwiki/index.php/Linear_1D_Beam
The link tells me that it is in Matrix Market format, but I am unsure how to extract the M, E, K, B, and C matrices from the attached .m file. Could someone help me extract the data? I'd like to have access to the M, E, K, B, and C matrices the correspond to the following equation:

Here is what the .m file, LF10.m, looks like. There are 18 rows. There is also a .b, .c, .e, and .k file:

- Thank you
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jonas-schulze
le 12 Juil 2022
Modifié(e) : jonas-schulze
le 12 Juil 2022
load LF10.m
M = spconvert(LF10(2:end,:))
load LF10.m
m = LF10(1, 1)
n = LF10(1, 2)
i = LF10(2:end, 1)
j = LF10(2:end, 2)
v = LF10(2:end, 3)
M = sparse(i, j, v, m, n)
If the underlying matrix is symmetric, the market file will only contain half the matrix. In this case it's the lower triangular part, but I don't know whether it always is.
D = diag(diag(M))
L = tril(M, -1)
M = L + D + L'
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Alan Stevens
le 15 Juil 2021
Do you mean like this:
%%MatrixMarket matrix coordinate real symmetric
% System: M x_dotdot + E x_dot + K x = B u
% y = C x
%
% Steel beam, 5 nodes
% Properties: Length: 0.1 m, Density: 8000 kg/m^3, Diameter: 1 mm,
% Modulus of elasticity: 2.0e11 Pa, Poisson ratio: 0.29,
% Contr.of M to damping: 1e2, Contr. of K to damping: 1e-2.
% The output node is the node in the middle.
%
Mx = [18 18 50
1 1 8.2666855418381347E-11
2 1 2.3970604543209878E-08
2 2 5.1946160853333332E-05
3 1 -6.1709237860082308E-11
3 3 1.6533371083676269E-10
4 2 8.9335862399999995E-06
4 3 2.3970604543209878E-08
4 4 5.1946160853333332E-05
5 2 -2.3970604543209878E-08
5 3 -6.1709237860082308E-11
5 5 1.6533371083676269E-10
6 4 8.9335862399999995E-06
6 5 2.3970604543209878E-08
6 6 5.1946160853333332E-05
7 4 -2.3970604543209878E-08
7 5 -6.1709237860082308E-11
7 7 1.6533371083676269E-10
8 6 8.9335862399999995E-06
8 7 2.3970604543209878E-08
8 8 5.1946160853333332E-05
9 6 -2.3970604543209878E-08
9 7 -6.1709237860082308E-11
9 9 1.6533371083676269E-10
10 8 8.9335862399999995E-06
10 9 2.3970604543209878E-08
10 10 5.1946160853333332E-05
11 8 -2.3970604543209878E-08
11 9 -6.1709237860082308E-11
11 11 1.6533371083676269E-10
12 10 8.9335862399999995E-06
12 11 2.3970604543209878E-08
12 12 5.1946160853333332E-05
13 10 -2.3970604543209878E-08
13 11 -6.1709237860082308E-11
13 13 1.6533371083676269E-10
14 12 8.9335862399999995E-06
14 13 2.3970604543209878E-08
14 14 5.1946160853333332E-05
15 12 -2.3970604543209878E-08
15 13 -6.1709237860082308E-11
15 15 1.6533371083676269E-10
16 14 8.9335862399999995E-06
16 15 2.3970604543209878E-08
16 16 5.1946160853333332E-05
17 14 -2.3970604543209878E-08
17 15 -6.1709237860082308E-11
17 17 1.6533371083676269E-10
18 16 -2.3970604543209878E-08
18 17 -6.1709237860082308E-11
18 18 8.2666855418381347E-11];
M = zeros(18,18);
for r = 2:51
M(Mx(r,1), Mx(r,2)) = Mx(r,3);
end
disp(M)
5 commentaires
Alan Stevens
le 16 Juil 2021
Yes, that's the same matrix I regenerated from your file (the numbers are just displayed slightly differently).
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