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Hello, it s another solution: function m = year2016(A,B) day_no = datenum(2016,A,1)-datenum(2016,0,1); day_mo...
environ 8 ans il y a | 0
Write a function called day_diff that takes four scalar positive integer inputs, month1, day1, month2, day2. These represents the birthdays of two children who were born in 2015. The function returns a positive integer scalar that is equal to the dif
Here there is more basic solution: function dd = day_diff(m1, d1, m2, d2) A = [31 28 31 30 31 30 31 31 30 31 30 31...
environ 8 ans il y a | 0
