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Dang Quang Chien


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A résolu


Find best placement for ordered dominoes (harder)
Given a list of ordered pairs, find the order they should be placed in a line, such that the sum of the absolute values of the d...

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A résolu


Find perfect placement of non-rotating dominoes (easier)
Given a list of ordered pairs, find the order they should be placed in a line, such that the sum of the absolute values of the d...

presque 3 ans il y a

A résolu


Find MPG of Lightest Cars
The file |cars.mat| contains a table named |cars| with variables |Model|, |MPG|, |Horsepower|, |Weight|, and |Acceleration| for ...

plus de 3 ans il y a

A résolu


Plot Damped Sinusoid
Given two vectors |t| and |y|, make a plot containing a blue ( |b| ) dashed ( |--| ) line of |y| versus |t|. Mark the minimum...

plus de 3 ans il y a

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Is A the inverse of B?
Given a matrix A and a matrix B, is A the inverse of B? >>A=[2,4;3,5]; >>B=[-2.5,2;1.5,-1]; >>isInverse...

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Rotate Matrix @180 degree
Rotate Matrix @180 degree Example A=[8 1 6; 3 5 7; 4 9 2], then answer would be [2 9 4;...

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Converts numbers into characters
Converts numbers into characters

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Find the max element of the array
Find the max element of the array

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Square root
Given x (a matrix), give back another matrix, where all the elements are the square roots of x's elements.

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Calculate the average value of the elements in the array
Calculate the average value of the elements in the array

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to the 2 all elements
to the 2 all elements

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the average value of the elements
Calculate the average value of the elements in the array

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Double all elements in the array
Duplicate all elements in the array

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calculate the length of matrix
input 1 array, calculate the length

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Draw a '0' in a one matrix!

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Highly divisible triangular number (inspired by Project Euler 12)
Triangular numbers can be calculated by the sum from 1 to n. For example, the first 10 triangular numbers are: 1, 3, 6, 10, ...

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Divisible by 3
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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Divisible by 7
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

presque 4 ans il y a

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Project Euler: Problem 8, Find largest product in a large string of numbers
Find the greatest product of five consecutive digits in an n-digit number. 73167176531330624919225119674426574742355349194934...

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Divisible by 16
Write a function to determine if a number is divisible by 16. This can be done by a few different methods. Here are two: # If...

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Divisible by 15
Write a function to determine if a number is divisible by 15. If a number is <http://www.mathworks.com/matlabcentral/cody/proble...

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Divisible by 14
Write a function to determine if a number is divisible by 14. If a number is <http://www.mathworks.com/matlabcentral/cody/proble...

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Divisible by 13
Write a function to determine if a number is divisible by 13. Similar to the number seven, this can be done by a few different m...

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Divisible by 12
Write a function to determine if a number is divisible by 12. Similar to the number six, this can be done by checking for divisi...

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Divisible by 11
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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Divisible by 10
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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A résolu


Divisible by 9
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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Divisible by 8
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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A résolu


Divisible by 6
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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A résolu


Divisible by 5
Pursuant to the <http://www.mathworks.com/matlabcentral/cody/problems/42404-divisible-by-2 first problem> in this series, this o...

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